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Proof step 12 from proof ushort-plus (previous step)

¬(0 ≤ s2i(sho) + s2i(sho0) ∧ s2i(sho) + s2i(sho0) < 65536), s2i(sho) + s2i(sho0) < 0, s2i(sho0) < 0, 0 ≤ s2i(sho) ⊦ us2i(i2s(s2i(sho) + s2i(sho0))) = s2i(sho) + s2i(sho0) + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i + j = j + i;