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Proof step 3 from proof ushort-plus (previous step)

¬ s2i(sho) < 0 ⊦ us2i(sho) + us2i(sho0) < 2 ^ 16 → us2i(i2s(s2i(sho) + s2i(sho0))) = us2i(sho) + us2i(sho0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ushort-pos: ⊦ 0 ≤ s2i(sho) → us2i(sho) = s2i(sho);% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;