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Proof step 7 from proof ushort-plus (previous step)

0 ≤ s2i(sho), s2i(sho) + s2i(sho0) < 65536, 0 ≤ s2i(sho0) ⊦ us2i(i2s(s2i(sho) + s2i(sho0))) = s2i(sho) + s2i(sho0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ 0 ≤ i ∧ i < 65536 → us2i(i2s(i)) = i

Rule argument

name: ushort-pos-01 rotate: F subst: [i] → [s2i(sho) + s2i(sho0)]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ 0 ≤ i ∧ 0 ≤ j → ¬ i + j < 0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0); Used terms: s2i(sho) + s2i(sho0)