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Proof step 9 from proof ushort-plus (previous step)

s2i(sho0) < 0, (2 ^ 16 + s2i(sho0)) + s2i(sho) < 65536, 0 ≤ s2i(sho) ⊦ us2i(i2s(s2i(sho) + s2i(sho0))) = (2 ^ 16 + s2i(sho0)) + s2i(sho)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i + j < j ↔ i < 0;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;