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Proof step 10 from proof ushort-pos-01 (previous step)

s2i(i2s(i)) < 0, i < 65536, 0 ≤ i ⊦ 2 ^ 16 + s2i(i2s(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
s2i(i2s(i)) < 0, 0 ≤ i, i < 65536 ⊦ s2i(i2s(i)) + 65536 = i

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)