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Proof step 13 from proof ushort-pos-01 (previous step)

¬(~32768 ≤ i ∧ i ≤ 32767), s2i(i2s(i)) < 0, 0 ≤ i, i < 65536 ⊦ s2i(i2s(i)) + 65536 = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 < i, 32767 < i, i < 65536, 0 ≤ i, s2i(i2s(i)) < 0 ⊦ s2i(i2s(i)) + 65536 = i

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i ≤ j ↔ j < i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;