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Proof step 16 from proof ushort-pos-02 (previous step)

s2i(i2s(i)) < 0, ~65536 ≤ i, i < 0 ⊦ 2 ^ 16 + s2i(i2s(i)) = i + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
~65536 ≤ i, i < 0, s2i(i2s(i)) < 0 ⊦ s2i(i2s(i)) = i

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = i + i0 ↔ j = i0;