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Proof step 4 from proof ushort-pos-02 (previous step)

¬ s2i(i2s(i)) < 0, ~65536 ≤ i, i < 0 ⊦ us2i(i2s(i)) = i + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ s2i(i2s(i)), i < 0, ~65536 ≤ i ⊦ s2i(i2s(i)) = i + 65536

Rule argument

Additional information

Used simplifier rules: ushort-pos: ⊦ 0 ≤ s2i(sho) → us2i(sho) = s2i(sho);% ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;