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Proof step 7 from proof ushort-pos-02 (previous step)

¬(~32768 ≤ i ∧ i ≤ 32767), 0 ≤ s2i(i2s(i)), i < 0, ~65536 ≤ i ⊦ s2i(i2s(i)) = i + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 ≤ s2i(i2s(i)), i < 0, ~65536 ≤ i, i < ~32768 ⊦ s2i(i2s(i)) = i + 65536

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ ¬ i ≤ j ↔ j < i;