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Proof step 4 from proof ushort-zero-01 (previous step)

s2i(sho) < 0 ⊦ ~65536 = s2i(sho) ↔ s2i(sho) = 0

User applied rule case distinction

And obtained the following new goals

Proof step 5:
~65536 = s2i(sho), s2i(sho) < 0 ⊦ s2i(sho) = 0

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)