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Proof step 4 from proof band-65535-pos (previous step)

¬ abs(bytes2int(bytes)) < 65536, # bytes ≤ 2, 0 ≤ bytes2int(bytes) ⊦ bytes = [], bytes2int(bytes) % 65536 = bytes2int(bytes)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# bytes ≤ 2, 0 ≤ bytes2int(bytes), 65536 ≤ bytes2int(bytes), 0 < bytes2int(bytes) ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ j ≤ j0 ∧ 0 < j → i % j ≠ j0;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ 0 ≤ i → abs(i) = i;