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Proof step 2 from proof bits2bits-inj (previous step)

# bits % 8 = 0 ⊦ bits = [], bytes2bits(bits2bytes(bits)) = bits

User applied rule induction

And obtained the following new goals

Proof step 3:
# bits % 8 = 0, ∀ bits0. # bits0 < # bits → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bits = [] ∨ bytes2bits(bits2bytes(bits)) = bits

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits