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Proof step 20 from proof bits2bits-inj (previous step)

# lastn(8, bits) = 8, # bits = n * 8, 8 < n * 8, ∀ bits0. # bits0 < n * 8 → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bits = [], bytes2bits(bits2bytes(firstn(n * 8 - 8, bits))) + lastn(8, bits) = bits, (n * 8 - 8) % 8 = 0, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ m ≠ 0 → m * n - n = (m - 1) * n subst: [n, m] → [8, n] rotate: F spec: nat-mult inst: name: dist-sub-01

Additional information

Used simplifier rules: n ≠ 0 ⊦ (m * n) % n = 0;% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m; Used terms: 8, n