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Proof step 26 from proof bits2bits-inj (previous step)

# bits % 8 = 0, # bits ≤ 8, ∀ bits0. # bits0 < # bits → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bits = [], byte2bits(i2b(bits2int(bits))) = bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ # bits = 8 → byte2bits(i2b(bits2int(bits))) = bits

Rule argument

name: byte2bits8 rotate: F subst: [bits] → [bits]

Additional information

Used simplifier rules: ⊦ m ≠ n → (m ≤ n ↔ m < n);% ⊦ m < n → m % n = m;% ⊦ # bits = 0 ↔ bits = []; Used terms: bits