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Proof step 4 from proof bits2bits-inj (previous step)

# bits % 8 = 0, ∀ bits0. # bits0 < # bits → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bytes2bits(bits2bytes(bits)) = bits, bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '
Proof step 6:
¬ # bits ≤ 8, # bits % 8 = 0, ∀ bits0. # bits0 < # bits → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bytes2bits(bits2bytes(bits)) = bits, bits = []
Proof step 25:
# bits ≤ 8, # bits % 8 = 0, ∀ bits0. # bits0 < # bits → # bits0 % 8 = 0 → bits0 = [] ∨ bytes2bits(bits2bytes(bits0)) = bits0 ⊦ bytes2bits(i2b(bits2int(bits)) ') = bits, bits = []

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [bits]

Additional information

Used terms: bits