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Proof step 128 from proof bits2bits-sgn (previous step)

true ∈ bytes2bits(bits2bytes(firstn(# bits - 8, bits))) ∧ false ∈ bytes2bits(bits2bytes(firstn(# bits - 8, bits))), 8 < # bits, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ sgn(bytes2bits(bits2bytes(bits0))) = sgn(bits0) ⊦ sgn(bytes2bits(bits2bytes(firstn(# bits - 8, bits)))) + byte2bits(i2b(bits2int(lastn(8, bits)))) = sgn(bits), bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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