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Proof step 29 from proof bits2bytes-app (previous step)

8 = # bits0, ∀ bits1, bits2. # bits2 + # bits1 < # bits + 8 → # bits1 % 8 = 0 → bits2 = [] ∨ bits1 = [] ∨ bits2bytes(bits2 + bits1) = bits2bytes(bits2) + bits2bytes(bits1) ⊦ i2b(bits2int(bits0)) ' = bits2bytes(bits0), bits0 = [], bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 30:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [bits0]

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n ∧ m = n0 → n0 < n; (forward)% ⊦ m < n ∧ n = n0 → m < n0; (forward)% ⊦ m < n → ¬ n < m; Used terms: bits0