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Proof step 11 from proof bits2bytes-fill (previous step)

#(mklist(bits.first, 8 - # bits) + bits) ≤ 8, m * 8 = 0, # bits < 8 ⊦ bits = [], bits2bytes(bits) = i2b(bits2int(mklist(bits.first, 8 - # bits) + bits)) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
m * 8 = 0, # bits < 8 ⊦ bits = [], bits2bytes(bits) = i2b(bits2int(mklist(bits.first, 8 - # bits) + bits)) '

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ n < m → (m - n) + n = m;% ⊦ # mklist(boolvar, n) = n;% ⊦ #(bits + bits0) = # bits + # bits0;