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Proof step 20 from proof bits2bytes-fill (previous step)

((8 - # bits % 8) + # bits) % 8 = 0, 8 < (8 - # bits % 8) + # bits ⊦ 8 + # bits = # bits % 8, bits = [], # bits % 8 = 0, bits2bytes(bits) = bits2bytes(firstn(8, mklist(bits.first, 8 - # bits % 8) + bits)) + bits2bytes(restn(8 - (8 - # bits % 8), bits))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ m0 ≤ n ∧ n ≤ m → m - (n - m0) = (m - n) + m0
Proof step 22:
# bits % 8 ≤ 8 ∧ 8 ≤ 8, ((8 - # bits % 8) + # bits) % 8 = 0, 8 < (8 - # bits % 8) + # bits ⊦ 8 + # bits = # bits % 8, bits = [], # bits % 8 = 0, bits2bytes(bits) = bits2bytes(firstn(8, mklist(bits.first, 8 - # bits % 8) + bits)) + bits2bytes(restn((8 - 8) + # bits % 8, bits))

Rule argument

seq: ⊦ m0 ≤ n ∧ n ≤ m → m - (n - m0) = (m - n) + m0 subst: [m0, n, m] → [# bits % 8, 8, 8] rotate: F spec: nat inst: name: sub-succ

Additional information

Used simplifier rules: n ≠ 0 ⊦ m % n ≤ n; Used terms: # bits % 8, 8, 8