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Proof step 32 from proof bits2bytes-fill (previous step)

# bits = m * 8 + n, n < m * 8 + 7, n < 8, # bits ≤ 8, n < m * 8 + 8 ⊦ m = 0, i2b(bits2int(bits)) ' = bits2bytes(firstn(8, mklist(bits.first, 8 - n) + bits)) + bits2bytes(restn(n, bits)), n = 0, bits = []

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags:

Additional information