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Proof step 6 from proof bits2bytes-len-02 (previous step)

# bits = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0 ⊦ bits = [], n = 0, (# bits - 1) / 8 = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# bits = m * 8 + n, n < 8 ⊦ (# bits - 1) / 8 = m, n = 0, bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)