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Proof step 15 from proof bits2bytes-len (previous step)

# bits2bytes(firstn(# bits - 8, bits)) = 1 + (# bits - 8 - 1) / 8, 8 < # bits, 9 ≤ # bits, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ # bits2bytes(bits0) = (# bits0 - 1) / 8 + 1 ⊦ bits = [], (# bits - 8 - 1) / 8 = (# bits - 1 - 8) / 8

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ m - n - n0 = m - n0 - n subst: [n0, n, m] → [1, 8, # bits] rotate: F spec: nat inst: name: shift

Additional information

Used terms: 1, 8, # bits