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Proof step 3 from proof bits2bytes-len (previous step)

true, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ # bits2bytes(bits0) = (# bits0 - 1) / 8 + 1 ⊦ bits = [] ∨ # bits2bytes(bits) = (# bits - 1) / 8 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ # bits2bytes(bits0) = (# bits0 - 1) / 8 + 1 ⊦ # bits2bytes(bits) = (# bits - 1) / 8 + 1, bits = []

Proof step 3 from proof bits2bytes-len (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information