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Proof step 7 from proof bits2bytes-len (previous step)

8 < # bits, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ # bits2bytes(bits0) = (# bits0 - 1) / 8 + 1 ⊦ bits = [], # bits2bytes(bits) = (# bits - 1) / 8 + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ 8 < # bits → bits2bytes(bits) = bits2bytes(firstn(# bits - 8, bits)) + i2b(bits2int(lastn(8, bits)))
Proof step 9:
8 < # bits, 8 < # bits, ∀ bits0. # bits0 < # bits → true → bits0 = [] ∨ # bits2bytes(bits0) = (# bits0 - 1) / 8 + 1 ⊦ bits = [], #(bits2bytes(firstn(# bits - 8, bits)) + i2b(bits2int(lastn(8, bits)))) = (# bits - 1) / 8 + 1

Rule argument

name: bits2bytes-rec rotate: F subst: [bits] → [bits]

Additional information

Used terms: bits