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Proof step 15 from proof bits2bytes-mklist-02 (previous step)

8 < # mklist(true, n), n % 8 = 0, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(true, n0)) = mklist(i2b(~1), n0 / 8) ⊦ bits2bytes(firstn(# mklist(true, n) - 8, mklist(true, n))) + i2b(bits2int(lastn(8, mklist(true, n)))) = mklist(i2b(~1), n / 8), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)% ⊦ m < n → n ≠ 0;% ⊦ bytes + by = bytes + by ';% ⊦ # mklist(boolvar, n) = n;