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Proof step 24 from proof bits2bytes-mklist-02 (previous step)

8 ≤ n0 * 8, 8 < n0 * 8, ∀ n1. n1 < n0 * 8 → n1 % 8 = 0 → n1 = 0 ∨ bits2bytes(mklist(true, n1)) = mklist(i2b(~1), n1 / 8) ⊦ bits2bytes(mklist(true, n0 * 8 - 8)) + i2b(bits2int(mklist(true, 8))) ' = mklist(i2b(~1), n0), n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
8 < n0 * 8, ∀ n1. n1 < n0 * 8 → n1 % 8 = 0 → n1 = 0 ∨ bits2bytes(mklist(true, n1)) = mklist(i2b(~1), n1 / 8) ⊦ n0 = 0, bits2bytes(mklist(true, n0 * 8 - 8)) + i2b(bits2int(true ' + true ' + true ' + true ' + true ' + true ' + true ' + true ')) ' = mklist(i2b(~1), n0)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n;% ⊦ m * n = n * m;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ mklist(boolvar, 0) = [];%n ≠ 0 ⊦ mklist(true, (* n)) = true ' + mklist(true, n -1);