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Proof step 6 from proof bits2bytes-mklist-02 (previous step)

¬ 8 < # mklist(true, n), n % 8 = 0, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(true, n0)) = mklist(i2b(~1), n0 / 8) ⊦ bits2bytes(mklist(true, n)) = mklist(i2b(~1), n / 8), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
n % 8 = 0, n ≤ 8, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(true, n0)) = mklist(i2b(~1), n0 / 8) ⊦ bits2bytes(mklist(true, n)) = mklist(i2b(~1), n / 8), n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;% ⊦ # mklist(boolvar, n) = n;