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Proof step 22 from proof bits2bytes-mklist-03 (previous step)

(n - n % 8) % 8 = 0, 8 < n ⊦ n - n % 8 = 0, bits2bytes(mklist(true, n % 8)) + mklist(i2b(~1), (n - n % 8) / 8) = i2b(~1) ' + mklist(i2b(~1), n / 8), n % 8 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) '
Proof step 24:
# mklist(true, n % 8) ≤ 8, (n - n % 8) % 8 = 0, 8 < n ⊦ n - n % 8 = 0, i2b(bits2int(mklist(true, n % 8))) ' + mklist(i2b(~1), (n - n % 8) / 8) = i2b(~1) ' + mklist(i2b(~1), n / 8), n % 8 = 0

Rule argument

name: bits2bytes-base rotate: F subst: [bits] → [mklist(true, n % 8)]

Additional information

Used simplifier rules: ⊦ # mklist(boolvar, n) = n;%n ≠ 0 ⊦ m % n ≤ n; Used terms: mklist(true, n % 8)