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Proof step 19 from proof bits2bytes-mklist (previous step)

n % 8 = 0, 8 < n, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ bits2bytes(mklist(false, n - 8)) + i2b(bits2int(lastn(8, mklist(false, n)))) ' = mklist(i2b(0), n / 8)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ m ≤ n → lastn(m, mklist(boolvar, n)) = mklist(boolvar, m)
Proof step 21:
8 ≤ n, n % 8 = 0, 8 < n, ∀ n0. n0 < n → n0 % 8 = 0 → n0 = 0 ∨ bits2bytes(mklist(false, n0)) = mklist(i2b(0), n0 / 8) ⊦ bits2bytes(mklist(false, n - 8)) + i2b(bits2int(mklist(false, 8))) ' = mklist(i2b(0), n / 8)

Rule argument

seq: ⊦ m ≤ n → lastn(m, mklist(boolvar, n)) = mklist(boolvar, m) subst: [n, boolvar, m] → [n, false, 8] rotate: F spec: list-del inst: bitlista name: lastn-mklist

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m; Used terms: n, false, 8