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Proof step 2 from proof bits2bytes-rec-01 (previous step)

8 < # bits ⊦ # bits % 8 = 0, bits2bytes(bits) = bits2bytes(firstn(# bits % 8, bits)) + bits2bytes(restn(# bits % 8, bits)), bits = []

User applied rule cut formula

And obtained the following new goals

Proof step 3:
bits = firstn(# bits % 8, bits) + restn(# bits % 8, bits), 8 < # bits ⊦ # bits % 8 = 0, bits2bytes(bits) = bits2bytes(firstn(# bits % 8, bits)) + bits2bytes(restn(# bits % 8, bits)), bits = []
Proof step 13:
8 < # bits ⊦ bits = firstn(# bits % 8, bits) + restn(# bits % 8, bits), # bits % 8 = 0, bits2bytes(bits) = bits2bytes(firstn(# bits % 8, bits)) + bits2bytes(restn(# bits % 8, bits)), bits = []

Rule argument

fma: bits = firstn(# bits % 8, bits) + restn(# bits % 8, bits)

Additional information

Used formulas: bits = firstn(# bits % 8, bits) + restn(# bits % 8, bits)