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Proof step 9 from proof bits2bytes-rec-01 (previous step)

# bits = m * 8 + n, n + 1 < # bits, n < 8, 8 < # bits, n < # bits ⊦ n = 0, bits2bytes(firstn(n, bits) + restn(n, bits)) = bits2bytes(firstn(n, bits)) + bits2bytes(restn(n, bits)), bits = [], m * 8 = 1, m = 0, (# bits - n) % 8 = 0 ∧ restn(n, bits) ≠ []

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags:

Additional information