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Proof step 1 from proof bits2bytes-rec-02 (conclusion)

⊦ # bits % 8 = 0 ∧ 8 < # bits → bits2bytes(bits) = bits2bytes(firstn(8, bits)) + bits2bytes(restn(8, bits))

User applied rule induction

And obtained the following new goals

Proof step 2:
true, ∀ bits0. # bits0 < # bits → true → # bits0 % 8 = 0 ∧ 8 < # bits0 → bits2bytes(bits0) = bits2bytes(firstn(8, bits0)) + bits2bytes(restn(8, bits0)) ⊦ # bits % 8 = 0 ∧ 8 < # bits → bits2bytes(bits) = bits2bytes(firstn(8, bits)) + bits2bytes(restn(8, bits))

Rule argument

indvar: # bits wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # bits