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Proof step 1 from proof bits2int-2pot (conclusion)

⊦ ¬ true ∈ bits → bytes2int(bits2bytes(true ' + bits)) = ~(2 ^ n→i(# bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ 2 ^ n→i(# bits) + bytes2int(bits2bytes(true ' + bits)) = 0, true ∈ bits

Rule argument

Additional information

Used simplifier rules: ⊦ ~ i = j ↔ i + j = 0;