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Proof step 2 from proof bits2int-neg (previous step)

bytes2int(bits2bytes(bits)) < 0 ⊦ bits = [], bits.first

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ bits ≠ [] → (0 ≤ bytes2int(bits2bytes(bits)) ↔ ¬ bits.first)
Proof step 4:
bits ≠ [] → (0 ≤ bytes2int(bits2bytes(bits)) ↔ ¬ bits.first), bytes2int(bits2bytes(bits)) < 0 ⊦ bits = [], bits.first

Rule argument

name: bits2int-pos subst: [bits] → [bits]

Additional information

Used terms: bits