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Proof step 17 from proof bits2int-pos (previous step)

#(boolvar ' + bits0) % 8 ≠ 0 ∧ 8 < #(boolvar ' + bits0), 7 < # bits0 ⊦ (# bits0 + 1) % 8 = 0, 0 ≤ bytes2int(bits2bytes(firstn(#(boolvar ' + bits0) % 8, boolvar ' + bits0)) + bits2bytes(restn(#(boolvar ' + bits0) % 8, boolvar ' + bits0))) ↔ ¬ boolvar, bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: n0 < n ⊦ (* n) < m0 + (* n0) ↔ n - n0 < m0;% ⊦ m + 1 ≠ 0;% ⊦ restn(n + 1, bits) = restn(n, bits.rest);% ⊦ boolvar + bits = boolvar ' + bits;% ⊦ (boolvar ' + bits).rest = bits;% ⊦ (boolvar ' + bits).first ↔ boolvar;% ⊦ firstn(n + 1, bits) = bits.first + firstn(n, bits.rest);%n ≠ 0 ⊦ (m + 1) % n ≠ 0 → (m + 1) % n = m % n + 1;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;