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Proof step 66 from proof bits2int-pos (previous step)

fillsgn(8, uint2bits(bits2uint(firstn(# bits0 % 8, bits0)))) + bytes2bits(bits2bytes(restn(# bits0 % 8, bits0))) ≠ [], (fillsgn(8, uint2bits(bits2uint(firstn(# bits0 % 8, bits0)))) + bytes2bits(bits2bytes(restn(# bits0 % 8, bits0)))).first, 0 ≤ bits2uint(firstn(# bits0 % 8, bits0)), # bits0 % 8 < # bits0, # bits0 % 8 ≤ 7, 7 < # bits0, bits2uint(firstn(# bits0 % 8, bits0)) ≤ 127 ⊦ (# bits0 + 1) % 8 = 0, bits0 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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