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Proof step 8 from proof bits2int-pos (previous step)

(# bits0 + 1) % 8 = 0, 7 < # bits0 ⊦ 0 ≤ bytes2int(bits2bytes(boolvar ' + bits0)) ↔ ¬ boolvar, bits0 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ bytes2int(bytes) = bits2int(bytes2bits(bytes))
Proof step 10:
(# bits0 + 1) % 8 = 0, 7 < # bits0 ⊦ 0 ≤ bits2int(bytes2bits(bits2bytes(boolvar ' + bits0))) ↔ ¬ boolvar, bits0 = []

Rule argument

name: bytes2int rotate: F subst: [bytes] → [bits2bytes(boolvar ' + bits0)]

Additional information

Used terms: bits2bytes(boolvar ' + bits0)