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Proof step 1 from proof bits2int-zero-ls (conclusion)

⊦ bytes ≠ [] → (bits2int(bytes2bits(bytes)) < 0 ↔ b2i(bytes.first) < 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ bytes = [], bits2int(bytes2bits(bytes)) < 0 ↔ ¬ 0 ≤ b2i(bytes.first)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;