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Proof step 14 from proof byte2bits-val (previous step)

8 = n + # int2bits(b2i(by)), # int2bits(b2i(by)) ≤ 8, b2i(by) < 0 ⊦ bits2uint(mklist(true, n)) * 2 ^ n→i(# int2bits(b2i(by))) + bits2uint(int2bits(b2i(by))) = b2i(by) + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2uint(bits) = 2 ^ n→i(# bits) - 1 subst: [bits] → [mklist(true, n)] rotate: F spec: int2bits inst: name: bits2uint-ones

Additional information

Used terms: mklist(true, n)