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Proof step 17 from proof byte2bits-val (previous step)

8 = # int2bits(b2i(by)), b2i(by) < 0 ⊦ bits2uint(int2bits(b2i(by))) = b2i(by) + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ j < 0 → bits2uint(int2bits(j)) = 2 ^ n→i(# int2bits(j)) + j subst: [j] → [b2i(by)] rotate: F spec: int2bits inst: name: int2uint-neg

Additional information

Used simplifier rules: ⊦ i + j = i + i0 ↔ j = i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: b2i(by)