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Proof step 31 from proof byte2bits-val (previous step)

0 ≤ n→i(# int2bits(b2i(by))) ∧ 0 ≤ n→i(n), 8 = n + # int2bits(b2i(by)), # int2bits(b2i(by)) ≤ 8, b2i(by) < 0 ⊦ n = 0, 2 ^ n→i(n + # int2bits(b2i(by))) = 256

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: rotate, discard

Proof step 31 from proof byte2bits-val (previous step)

User applied rule insert equation

And closed the goal!

Rule argument

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