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Proof step 4 from proof byte2bits-val (previous step)

b2i(by) < 0 ⊦ bits2uint(byte2bits(by)) = b2i(by) + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ byte2bits(by) = fillsgn(8, int2bits(b2i(by)))
Proof step 6:
b2i(by) < 0 ⊦ bits2uint(fillsgn(8, int2bits(b2i(by)))) = b2i(by) + 256

Rule argument

name: byte2bits rotate: F subst: [by] → [by]

Additional information

Used terms: by