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Proof step 3 from proof byte2bits-value (previous step)

⊦ bits2int(fillsgn(8, int2bits(b2i(by)))) = b2i(by)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ bits ≠ [] → bits2int(fillsgn(n, bits)) = bits2int(bits)

Rule argument

seq: ⊦ bits ≠ [] → bits2int(fillsgn(n, bits)) = bits2int(bits) subst: [bits, n] → [int2bits(b2i(by)), 8] rotate: F spec: int2bits inst: name: bits2int-fill

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ bits2int(int2bits(i)) = i;% ⊦ b2i(byi) = b2i(byj) ↔ byi = byj; Used terms: int2bits(b2i(by)), 8