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Proof step 1 from proof byte2bits8 (conclusion)
⊦ # bits = 8 → byte2bits(i2b(bits2int(bits))) = bits
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
# bits = 8 ⊦ byte2bits(i2b(bits2int(bits))) = bits
Rule argument
Additional information