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Proof step 2 from proof bytes2bits-nle (previous step)

2 ^ (8 * n→i(# bytes)) ≤ bits2uint(bytes2bits(bytes)) ⊦

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 3:
⊦ ¬ 2 ^ n→i(# bits) ≤ bits2uint(bits)

Rule argument

seq: ⊦ ¬ 2 ^ n→i(# bits) ≤ bits2uint(bits) subst: [bits] → [bytes2bits(bytes)] rotate: F spec: int2bits inst: name: bits2uint-nle

Additional information

Used simplifier rules: bytes2bits-length: ⊦ # bytes2bits(bytes) = i→n(8) * # bytes;% ⊦ n→i(m * n) = n→i(m) * n→i(n);% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i * j = j * i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: bytes2bits(bytes)