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Proof step 2 from proof bytes2bytes-fillsgn (previous step)

⊦ fillsgn(# bytes, int2bytes(bytes2int(bytes))) = bytes, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes
Proof step 4:
¬ # int2bytes(bytes2int(bytes)) ≥ # bytes ⊦ fillsgn(# bytes, int2bytes(bytes2int(bytes))) = bytes, bytes = []
Proof step 8:
# int2bytes(bytes2int(bytes)) ≥ # bytes ⊦ int2bytes(bytes2int(bytes)) = bytes, bytes = []

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [int2bytes(bytes2int(bytes)), # bytes]

Additional information

Used terms: int2bytes(bytes2int(bytes)), # bytes