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Proof step 9 from proof bytes2bytes-fillsgn (previous step)

# bytes ≤ # int2bytes(bytes2int(bytes)) ⊦ int2bytes(bytes2int(bytes)) = bytes, bytes = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ # bytes ≤ # int2bytes(bytes2int(bytes)) ∧ bytes ≠ [] → int2bytes(bytes2int(bytes)) = bytes

Rule argument

name: bytes2bytes-identity-01 rotate: F subst: [bytes] → [bytes]

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m ≤ n → (n < m ↔ false); Used terms: bytes