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Proof step 15 from proof bytes2bytes-first-neg (previous step)

b2i(by) = 0, b2i(int2bytes(bytes2int(by ' + by0 ' + bytes1)).first) < 0, 0 ≤ b2i(by0), ∀ by, bytes0. # bytes0 < #(by0 + bytes1) → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ i2b(i) ≠ i2b(j) → i ≠ j
Proof step 17:
¬ i2b(b2i(by)) ≠ i2b(0), b2i(by) = 0, b2i(int2bytes(bytes2int(by ' + by0 ' + bytes1)).first) < 0, 0 ≤ b2i(by0), ∀ by, bytes0. # bytes0 < #(by0 + bytes1) → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦

Rule argument

seq: ⊦ i2b(i) ≠ i2b(j) → i ≠ j subst: [j, i] → [0, b2i(by)] rotate: F spec: byte inst: name: i2b-noteq

Additional information

Used terms: 0, b2i(by)