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Proof step 22 from proof bytes2bytes-first-neg (previous step)

∀ by, bytes0. # bytes0 < # bytes → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦ b2i(by) ≠ ~1, bytes = [], b2i(int2bytes(bytes2int(by ' + bytes)).first) < 0 ↔ ¬ 0 ≤ b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
b2i(by) = ~1, 0 ≤ b2i(int2bytes(bytes2int(by ' + bytes)).first), ∀ by, bytes0. # bytes0 < # bytes → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦ bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;