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Proof step 4 from proof bytes2bytes-first-neg (previous step)

∀ by, bytes0. # bytes0 < # bytes → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦ b2i(int2bytes(bytes2int(by ' + bytes)).first) < 0 ↔ ¬ 0 ≤ b2i(by)

User applied rule cut formula

And obtained the following new goals

Proof step 5:
∀ by, bytes0. # bytes0 < # bytes → true → (b2i(int2bytes(bytes2int(by ' + bytes0)).first) < 0 ↔ ¬ 0 ≤ b2i(by)) ⊦ bytes = [], b2i(int2bytes(bytes2int(by ' + bytes)).first) < 0 ↔ ¬ 0 ≤ b2i(by)

Rule argument

fma: bytes = []

Additional information

Used simplifier rules: bytes2int-one: ⊦ bytes2int(by ') = b2i(by);%int2bytes-byte-01: ⊦ int2bytes(b2i(by)) = by ';% ⊦ bytes + [] = bytes;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by '.first = by;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used formulas: bytes = []